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SQL编写判断是否为工作日函数编写

最近的自己在写一些功能,遇到了对于工作日的判断,我就看了看sql,来吧!~(最近就是好疲惫)

我们一起看看(针对ORACLE)

1.声明:

CREATE OR REPLACE PACKAGE GZYW_2109_1214.PKG_FUN_GETDAY_HDAY AS /**  *  通过节假日代码获取指定的日期[查找基准日期前/后N自然/工作日的日期] * 注：此函数只适用于节假日表中只保存了节假日日期（非工作日记录）的情况 , * 警告：若没有设置范围内的节假日信息，此函数会计算出错误的返回日期 * _Stand_Date 基准日期, * C_MKT_Code 节假日代码, * N_Interval_Day 间隔天数(大于0向后查找,小于0向前查找,等于0返回基准日期), * C_Type 日期类型 'W'工作日,'D'自然日,'DW'自然日递延至工作日 */ Function GETDAY_HDAY(C_HDay_Code varchar2,D_Stand_Date date,N_Interval_Day int,C_Type varchar2) return Date; END PKG_FUN_GETDAY_HDAY;

2.主体

CREATE OR REPLACE PKG_FUN_GETDAY_HDAY AS Function getDay_HDay(C_HDay_Code varchar2, D_Stand_Date date, N_Interval_Day int, C_Type varchar2) return Date as D_Return Date; /*返回的日期*/ D_Start Date; /*区间开始日期*/ D_End Date; /*区间结束日期*/ D_Tmp Date; N_Count int := 1; C_Hday varchar2(20) := C_HDay_Code; begin D_Return := D_Stand_Date; /*判断参数是否合法*/ if (('W' != C_Type) AND ('D' != C_Type) and ('DW' != C_Type)) then return D_Return; else if (('D' = C_Type) or ('DW' = C_Type)) then D_Return := D_Stand_Date + N_Interval_Day; else /*工作日的推算*/ D_Start := D_Stand_Date; D_End := D_Stand_Date + N_Interval_Day; D_Return := D_End; while (true) loop exit when N_Count = 0; begin if (N_Interval_Day >= 1) then select /*+RESULT_CACHE*/ count(*) into N_Count from T_P_BI_HDAY_SUB a where a.C_HDay_Code = C_Hday and a.D_HDay > D_Start and a.D_HDay <= D_End and a.c_Date_Type = 'H' and a.N_Check_State = 1; if (N_Count > 0) then D_Start := D_End; D_End := D_End + N_Count; D_Return := D_End; else exit; /*退出*/ end if; else /*如果是逆序*/ if (D_Start > D_End) then D_Tmp := D_End; D_End := D_Start; D_Start := D_Tmp; end if; select /*+RESULT_CACHE*/ count(*) into N_Count from T_P_BI_HDAY_SUB a where a.C_HDay_Code = C_Hday and a.D_HDay >= D_Start and a.D_HDay < D_End and a.c_Date_Type = 'H' and a.N_Check_State = 1; if (N_Count > 0) then D_End := D_Start; D_Start := D_End - N_Count; D_Return := D_Start; else exit; /*退出*/ end if; end if; end; end loop; end if; if ('DW' = C_Type) and (N_Interval_Day>0) then N_Count:=1; while (true) loop exit when N_Count = 0; select /*+RESULT_CACHE*/ count(*) into N_Count from T_P_BI_HDAY_SUB a where a.C_HDay_Code = C_Hday and a.D_HDay = D_Return and a.c_Date_Type = 'H' and a.N_Check_State = 1; if N_Count!=0 then D_Return:=D_Return+1; end if; end loop; end if; end if; return D_Return; end; END PKG_FUN_GETDAY_HDAY;

3.检验

CN:基准日期(以哪个国家进行注明)

DATE ‘2023-10-08’:你要检验的日期

-1:代表去取前一日日期

‘W’:只取前面‘-1’也就是前一日的工作日

SELECT PKG_FUN_GETDAY_HDAY.GETDAY_HDAY('CN', DATE '2023-10-08', -1, 'W')   AS TEST_DATA  FROM  TEST_TABLE a  WHERE  ROWNUM<2;

运行结果: