基于Python实现一个简单的HttpServer,当用户在浏览器中输入IP地址:8000时，则会返回index.html页面内容，访问其它信息，则会返回错误信息(404)
"""
httpserver v1.0
1.获取来自浏览器的请求，
2.判断如果请求内容是 / ，就将index.html返回给客户端
3.如果请求是其它内容则返回404
"""
from socket import *def request(connfd):data = connfd.recv(4096)if not data:returncontent = data.decode()listcon = content.split("\r\n")reqinfo = listcon[0].split(" ")[1]print(reqinfo)if reqinfo == "/":with open("index.html") as f:response = "HTTP/1.1 200 OK\r\n"response += "Content-Type:text/html\r\n"response += "\r\n"response += f.read()print(response)else:response = "HTTP/1.1 404 Not Found\r\n"response += "Content-Type:text/html\r\n"response += "\r\n"response += "<h1>Sorry .....</.h1>\r\n"connfd.send(response.encode())sockfd = socket()
sockfd.setsockopt(SOL_SOCKET, SO_REUSEADDR, 1)
sockfd.bind(('0.0.0.0', 8000))
sockfd.listen(3)while True:connfd, addr = sockfd.accept()request(connfd)
<!DOCTYPE html>
<html lang="en">
<head><meta charset="UTF-8"><title>人生在世，好好努力</title>
</head>
<body>
好好努力吧，少年
</body>
</html>
~
